SELECTT EACHHHHHHH CORRECT ANWSERRRR

PLEASE HELP ME ASAP! I need to know the 3 equations to solve for the different types of points.

kiruha [24]

Answer:

f = 0

x > 2y

x ≤ 8

S ≥ 18

Step-by-step explanation:

Let 'f' represent the number of free throws.

Let 'x' represent the number of 2 - point baskets.

Let 'y' represent the number of 3 - point baskets.

Let S represent the Season high.

1) Ryan says he did not shoot any free throws.

⇒ f = 0

2) 2 - point baskets more than twice the number of 3 - point baskets.

⇒ x > 2y

3) Number of two points is less than or equal to 8.

⇒ x ≤ 8.

4) Last Season high, he had scored 18 points. Note that the problem says, Ryan equaled or bettered than last season high. That means he should got at least 18 points this season. So, the equation would be:

S ≥ 18

3 0

3 years ago

Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don

Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

$nP_r=\frac{n!}{(n-r)!}$

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

$\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}$

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

$_nC_r=\frac{n!}{(n-r)!r!}$

The formula can now be applied as follows;

$\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}$

If the order is not relevant, then the selection can be done in 56 ways.

3 0

1 year ago

How to find average value of a function over a given interval?

Strike441 [17]

f(x)=8x−6f(x)=8x-6 , [0,3][0,3]

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.(−∞,∞)(-∞,∞){x|x∈R}{x|x∈ℝ}f(x)f(x) is continuous on [0,3][0,3].f(x)f(x) is continuousThe average value of function ff over the interval [a,b][a,b] is defined as A(x)=1b−a∫baf(x)dxA(x)=1b-a∫abf(x)dx.A(x)=1b−a∫baf(x)dxA(x)=1b-a∫abf(x)dxSubstitute the actual values into the formula for the average value of a function.A(x)=13−0(∫308x−6dx)A(x)=13-0(∫038x-6dx)Since integration is linear, the integral of 8x−68x-6 with respect to xx is ∫308xdx+∫30−6dx∫038xdx+∫03-6dx.A(x)=13−0(∫308xdx+∫30−6dx)A(x)=13-0(∫038xdx+∫03-6dx)Since 88 is constant with respect to xx, the integral of 8x8x with respect to xx is 8∫30xdx8∫03xdx.A(x)=13−0(8∫30xdx+∫30−6dx)A(x)=13-0(8∫03xdx+∫03-6dx)By the Power Rule, the integral of xx with respect to xx is 12x212x2.A(x)=13−0(8(12x2]30)+∫30−6dx)

3 0

3 years ago

Vina has $4.70 in quarters, dimes and nickels in her purse. She has nine more dimes than quarters and four more nickels than qua

Aneli [31]

Step-by-step explanation:

Vina has $4.70 in quarters, dimes and nickels in her purse. She has nine more dimes than quarters and four more nickels than quarters. How many of each coin are in her purse?

nickels

dimes

quarters

4 0

2 years ago

(PLEASE HELP!!)

AlexFokin [52]

Answer:

X= 8

Y= 130

(8, 130)

Step-by-step explanation:

I used a graphing calculator to see where the two equations intersected.

Hope this helped :)

5 0

3 years ago

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