A and b can do a piece of work in 12 days. If a alone have to finish the job among b and c so
A and b=12
A (24 days alone without b)
So if b and c 15 days and c 20 days. If a have to do all I would add 24 and 15 and 20 which would be 59 days
Answer:
6.5
Step-by-step explanation:
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In this case it's, <span>log(u)^n = nlog(u)
so the answers are either </span><span>4 log (3x) or it could also be </span><span>4[log3 + log x]
</span>There is no need for the solution to be shown because this is a simple rule of properties of logarithms
