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3 years ago

Look below :) Everything is underneath, ty. Just need an answer by Wednesday

Mathematics

1 answer:

mamaluj [8]3 years ago

6 0

Answer:

Step-by-step explanation:

$\dfrac{3}{6}=\dfrac{9}{18}=\dfrac{27}{54}$

$\dfrac{3*3}{6*3}=\dfrac{9}{18}\\\\\\\dfrac{3*9}{6*9}=\dfrac{27}{54}$

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What is x + 8 = .5?

lions [1.4K]

X + 8 = 0.5

Take away 8 from both sides:

x = 0.5 - 8

x = -7.5

Answer: x = -7.5

7 0

4 years ago

Divide. 5 ÷ 5 /6 = help me fast !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Licemer1 [7]

The answer is 6

I hope this helped :)

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4 years ago

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What number must be added to the expression below to complete the<br> square?<br> x² - 18x

kiruha [24]

Answer:

$\boxed {\boxed {\sf 81}}$

Step-by-step explanation:

The standard form of a quadratic is:

$ax^2+bx+c$

To complete the square, the a (leading coefficient) must be 1 and there can only be terms with variables on one side.

The expression given:

$x^2-18x$

follows these rules. Next, we divide the b (linear coefficient) by 2, then square it. Basically:

$(\frac{b}{2})^2$

The b in the expression is -18.

$(\frac{-18}{2})^2$

$(-9)^2= -9*-9= 81$

This is the number that is added.

5 0

3 years ago

the 7th grade has 207 students. there are 23 more girls than boys in the grade. how many boys are in the 7th grade

valkas [14]

Answer:

92 boys

Step-by-step explanation:

I hope this helps! Have a lovely day!! :)

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3 years ago

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Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }$ and a bit more to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }$

Bring up the lower fraction and flip it to divide to get

$tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1}$ which of course simplifies to

-3. Choice A.

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4 years ago