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pogonyaev
3 years ago
10

An equation that shows the relationship between Fahrenheit and Celsius temperatures is F=9/5c+32, where F represents the tempera

ture in degrees Fahrenheit and C represents the temperature in degrees Celsius.
Solve this equation for C in terms of F
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0
F=9/5C+32   Original equation
F-32=9/5C  (subtract 32 from both sides)
5/9(F-32)=C  (multiply both sides by 5/9, the reciprocal of 9/5)
C=5/9(F-32)




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I think it's like the top answer is 6 the bottom 36.

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What is the slope of the line that passes through the points (1, 3) and (5, –2)?
Sergeu [11.5K]

m=-(5/4)

From left to right, (1,3) is first and then comes (5,-2). Always remember when finding slopes without equations, the rule is RISE over RUN, to the numerator and denominator, respectively.

The y value of the second coordinates becomes negative which is unlike the y value in the first coordinates, which means our slope is downward, meaning it has a negative sign in front.

In every slope, there’s a numerator, being the rise, and a denominator, being the run.

To find the rise, we must look at the y values. Starting at 3 going to -2 has a space of 5 units, making that our numerator.

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With these two numbers and the negative sign, we get -(5/4) as our slope.

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Which could be the measure of <br> A.) 38<br> B.) 42<br> C.) 44<br> D.) 52
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3 years ago
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Answer:

x=1+\sqrt{3} and x=1-\sqrt{3}

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

y=a\left(x-h\right)^2+k

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

y=a\left(x-1\right)^2-9...(i)

Plug given point (0, -6). into (i)

-6=a\left(0-1\right)^2-9

-6=a\left(-1\right)^2-9

-6=a\left(1\right)-9

-6+9=a

3=a

Plug a=3 into (i)

y=3\left(x-1\right)^2-9

Now to find x-intercept, we just plug y=0 and solve for x

y=3\left(x-1\right)^2-9

0=3\left(x-1\right)^2-9

9=3\left(x-1\right)^2

3=\left(x-1\right)^2

\pm \sqrt{3}=x-1

1+\pm \sqrt{3}=x

Hence final answer are

x=1+\sqrt{3} and x=1-\sqrt{3}

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