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satela [25.4K]
3 years ago
13

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0+ (2x + 1)

cot(x) Incorrect: Your answer is incorrect.
Mathematics
1 answer:
ElenaW [278]3 years ago
3 0

\displaystyle\lim_{x\to0^+}(2x+1)\cot x=\lim_{x\to0^+}\frac{2x+1}{\tan x}

As x\to0, the numerator approaches 1 while \tan x\to0, but since x\to0 from above we have \tan x>0, which suggests the limit is +\infty.

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