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Tomtit [17]
2 years ago
15

A firefighter training course is taking place in a high-rise building. The high-rise building where they practice is 48 stories

high. If the emergency happens on the top floor and the firefighters have already gone 29 stories, how many stories do they still need to go?
Mathematics
1 answer:
PIT_PIT [208]2 years ago
4 0

Answer:

29 stories - 49 stories = number of stories they need to go

28 - 49 = 21

the answer is 21

they have 21 more stories to go

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The month in which Company B's payment will first exceed Company A's payment is C) Month 7.

Step-by-step explanation:

Step 1:

Company A offers $6,000 for the first month and increases the salary each month by $5,000.

Company B offers $700 for the first month but doubles the payments each month.

We need to determine which month company B's payment is greater than company A's payment.

Step 2:

According to the table, at month 6 company A pays $31,000 while company B pays $22,400.

However after this month, in the seventh-month company A pays $36,000 while company B pays $44,800, which is higher than company A's salary.

So The month in which Company B's payment will first exceed Company A's payment is C) Month 7.

4 0
3 years ago
Please help and explain. i’m confused.
kondor19780726 [428]

Answer:  628

Step-by-step explanation:

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8 0
3 years ago
An observer at the top of a 532 foot cliff measures the angle of depression from the top of the cliff to a point on the ground t
Over [174]

Answer:

Distance from the base of the cliff to the point on the ground = 7608 feet

Step-by-step explanation:

Given: Height of the cliff is 532 feet, angle of depression from the top of the cliff to a point on the ground is equal to 4 degrees.

To find: distance from the base of the cliff to the point on the ground

Solution:

In ΔABC,

\angle ACB=4^{\circ}  (Alternate interior angles)

For any angle \theta, \tan \theta = side opposite to angle/side adjacent to angle

\tan C=\frac{AB}{BC}

Put AB=532\,,\,\angle C=4^{\circ}

\tan 4^{\circ}=\frac{532}{BC}\\\\BC=\frac{532}{\tan 4^{\circ}}\\\\=7607.95\\\\\approx 7608\,\,feet

Distance from the base of the cliff to the point on the ground = 7608 feet

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5 0
3 years ago
What is the rate of change of the line on the graph below?
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3 years ago
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Words problems involving length and money
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Answer:

12

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if you have two posters

6x2=12

so 12

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2 years ago
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