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Anvisha [2.4K]
4 years ago
14

4,500 kilobytes in 6 minutes

Mathematics
1 answer:
jeka944 years ago
6 0
Hi there!

As I saw in some other questions, I assumed this question is about unit rates..

So, the answer to this is 750 kb/m

Hope this helps!
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Connie Hamm demonstrates microwave ovens. She earn $5.00 per demonstration for the first 10 demonstrations and $6.00 for each de
Gemiola [76]
5*10+6*2+4*10.55=commission
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4 years ago
Not an actual test question but just curious:
saveliy_v [14]

well, when we use the word "the function" we're referring to the dependent part, which depends on the independent, y,x wise, we're referring to the function "y" or f(x) if you wish.

so for an exponential function

is the function ever positive only? it can be

is it negative only?  it can be

can it be both?  sure thing, most of the time it's both

we can say a function f(x) is always positive when the independent values of "x" yield a positive value only, mind you that when we're talking about "the function" we're really referring to the resulting values in a set, so can the values of the output no matter what "x" we use be always positive? sure, can they also be negative only? sure, how about both? sure thing.

notice the template in the picture below, we can transform any exponential function like the one above 2ˣ with some vertical shift upwards, and is always positive, or -2ˣ with a vertical shift downwards and it's always negative, or we can stretch it about and have -2ˣ shifted upwards so sometimes is positive, and sometimes is negative.

above the x-axis is always positive, below is negative, but with transformations on the parent function it can be any of the three types.

3 0
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Which number line shows the solution set for |y-9| <12
RUDIKE [14]

Answer:

Option c

y\geq-3 or y \leq 21

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function f(x) = |x|  x> 0 for all real numbers.

Then the inequation:

|y-9| \leq 12 has two cases

(y-9)    if y \geq 9  (i)

-(y-9)    if y < 9 (ii)

We solve the case (i)

y \leq 9 + 12\\y\leq21

We solve the case (ii)

-y +9 \leq 12\\-y \leq 12-9\\y \geq -3

Then the solution is:

y\geq-3 or y \leq 21

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Musya8 [376]

Answer:

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