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Levart [38]
3 years ago
9

I’m on Acellus and I have to combine like terms. I already got 12x but I can’t seem to get the next number. Can anyone help?

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

-9

Step-by-step explanation:

9x - 4 + 3x - 5 = 9x + 3x + (-4) + (-5)

12x + (-9)

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2) Tara is trying to find the nth term of the arithmetic sequence 5,8,11, and 14…. Which expression can Tara use to find the nth
juin [17]

Answer:

Below in bold.

Step-by-step explanation:

Nth term an = a1 + d(n - 1)   where a1 = term 1 and d = common difference.

Here a1 = 5 and d = 8-5 = 3.

So an = 5 + 3(n - 1)

15th term a15

=  5 + 3(15 - 1)

= 5 + 42

= 47.

4 0
2 years ago
What is the distance between two points(2,-6)(-7,1)
Ilia_Sergeevich [38]

Answer:

11.4

Step-by-step explanation:

Find the distance in the x-direction between the x-components:  2 - (-7) = 9.

Similarly: between the y-components:  1 - (-6) = 7

Apply the Pythagorean Theorem:  9^2 + 7^2 = d^2, where d is the desired distance:

81 + 49 = d^2, or d^2 = 130

The distance d is approximately √130 ≈ 11.4

3 0
2 years ago
Read 2 more answers
A certain recipe asks for 4/9 cup of granola , How much is needed to make 4/9 of a recipe
artcher [175]
4/9 times 4/9 is 16/81.
To make 4/9 of a recipe, 16/81 cups of granola needed.
7 0
3 years ago
4/5 + 3/4 =
marshall27 [118]

The topics you should learn are equating denominators and fractions. This is summing up simple fractions.

So we have to make denominators' numbers the same in order to sum up them all (we can sum fractions if the denominators are the same) , and we did it by cross product (that thing on the picture)

Equating by lcm (least common multiple) is the easiest way, because you might see bigger numbers on other questions, and cross product will bring much bigger numbers, so this technic might confuse you.

By the way lcm of 4 and 5 is already 20

Hope it helps!

5 0
3 years ago
A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.
iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- |E\ n\ B|

- |B|

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

B = \{6\}

E = \{2,4,6\}

Calculating the size of |E n B|

|E n B| = \{2,4,6\}\ n\ \{6\}

|E n B| = \{2,4,6\}

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

B = \{6\}

<em>The size = 1 because it contains 1 possible outcome</em>

8 0
3 years ago
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