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marta [7]
3 years ago
8

A popular computer card game keeps track of the number of games played and the number of games won on that computer. The cards a

re shuffled before each game, so the outcome of the game is independent from one game to the next and is based on the skill of the player. Let X represent the number of games that have been won out of 100 games. Under which of the following situations would X be a binomial random variable?
Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

Two players of equal skill level each played one game a day for 50 days and their skill level did not change from day to day.

Step-by-step explanation:

(A) The probability of player winning the game depends on the skill level . If  skill level increases the probability to win also increases. The probability of success (win) must remain constant for every trial (condition of binomial distribution), hence, this case cannot be modeled by a random binomial probability.

(B) Different skill levels means the probability of success differs between players, the probability of winning each game would differ between players,  hence. X can not be a binomial random variable.

(C) Same explanation as B  

(D) As both players have same skill set throughout the game, the probability of winning each of the n = 100 games is the cosnat; hence, X can be modeled as a binomial random variable

(E) Same explanation as B and C  

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At the city museum, child admission is $6.10 and adult admission is $9.90. On Friday, 142 tickets were sold for a total sales of
antoniya [11.8K]

Answer:

no of child tickets sold were 58

Step-by-step explanation:

Let the number of child ticket sold be x

cost of 1 child ticket = $6.10

Total cost of x child ticket = x*cost of 1 child ticket = = $6.10x

Let the number of adult ticket sold be y

cost of 1 adult ticket = $9.90

Total cost of y adult ticket = y*cost of 1 adult ticket = = $9.90y

Given total ticket sold = 142

Thus,

number of child ticket sold +  number of adult ticket sold = 142

x + y = 142   - equation 1

x = 142 -y  

Total sales of ticket = $1185.40

total sales of ticket  = Total cost of x child ticket + Total cost of x a dult ticket

6.10x + 9.90y = 1185.40

in this equation substituting x = 142 - y from equation 1

6.10(142 - y )  + 9.90y = 1185.40

=>866.2 - 6.10y + 9.90y = 1185.40

=> 3.80y = 1185.40 - 866.2

=> 3.80y = 319.2

=> y = 319.2/3.80 = 84

Thus, y = 84

x = 142 - y  = 142 - 84 = 58

Thus, no of child tickets sold were 58

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