Correct
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Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
First solve for the trig function 'cot'
Next take the sqrt of both sides (include plus/minus)
Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)
Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.
Next take the sqrt of both sides (include plus/minus)
Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)
Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.