For this case, what you must do is take out the area of two triangles and add it to the area of a rectangle to find the total area.
We have then:
Triangle area:
A = (1/2) * ((13-9) / (2)) * (10) = 10 in ^ 2
Rectangle area:
A = (9) * (10) = 90 in ^ 2
Total area:
At = 2 * (10) + 90 = 110 in ^ 2
answer:
110 in²
Convert the mixed number <span>21 <span>2/3</span></span><span> into an </span><span>improper fraction.
</span>15⋅<span>65/3
</span><span>Cancel 3 and 15.
</span><span>5⋅65
</span>Multiply 5<span> by </span>65<span> to get </span><span>325.
</span>325
Answer:
325
First three. A, b, c.
The triangle is a right triangle.
The triangle is a Pythagorean triple.
The triangles hypotenuse is 39 inches.
Pick 2 pairs of equations t<span>hen use addition and subtraction to eliminate </span>the same variable<span> from both pairs of equations then it is left with 2 variables
</span>Pick two pairs
<span><span>4x - 3y + z = - 10</span><span>2x + y + 3z = 0
</span></span>eliminate the same variable from each system
<span><span>4x - 3y + z = - 10</span>
<span>2x + y + 3z = 0</span>
<span>4x - 3y + z = - 10</span>
<span>-4x - 2y - 6z = 0</span>
<span>-5y - 5z = - 10</span>
<span>2x + y + 3z = 0</span>
<span>- x + 2y - 5z = 17</span>
<span>2x + y + 3z = 0</span>
<span>-2x + 4y - 10z = 34</span>
<span>5y - 7z = 34
</span></span>Solve the system of the two new equations:
<span><span>-5y - 5z = - 10</span>
<span>5y - 7z = 34</span>
<span>-12z = 24</span>
which is , <span>z = - 2</span>
<span>-5y - 5(- 2) = - 10</span>
<span>-5y = - 20</span>
wich is , <span>y = 4
</span></span>substitute into one of the original equations
<span>- x + 2y - 5z = 17</span>
<span>- x + 2(4) - 5(- 2) = 17</span>
<span>- x + 18 = 17</span>
<span>- x = - 1</span>
<span>x = 1</span>
<span>which is , </span><span>(x, y, z) = (1, 4, - 2)</span><span>
</span>Does 2(1) + 4 + 3(- 2) = 0<span> ? Yes</span><span>
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