9514 1404 393
Answer:
(a, b, c) = (-0.425595, 11.7321, 2.16667)
f(x) = -0.425595x² +11.7321x +2.16667
f(1) ≈ 13.5
Step-by-step explanation:
A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.
Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...
a = -0.425595
b = 11.7321
c = 2.16667
so
f(x) = -0.425595x² +11.7321x +2.16667
and f(1) ≈ 13.5
_____
<em>Additional comment</em>
Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.
The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
Hence, the value of x in x^yz = y^2 is
Read more about equations at:
brainly.com/question/2972832
#SPJ1
Answer:
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Answer:
Infinite Solutions
Step-by-step explanation:
If you look at the equation careful you will see this part "-4y+4y". If you see that the variables cancel each other out leaving 2=2. That means that for any value of y, 2=2. Because the variable cancels itself out it doesn't mater what the variable is. So there is an infinite amount of values you can have for "y".
Answer:
π
Step-by-step explanation:
Solve for x on the interval [0, 2pi]
Given the equation
Sinx = cosx + 1
Square both sides of the equation
Sin²x = (cos x + 1)²
Sin²x = cos²x + 2cos x + 1
Since Sin²x = 1 - cos²x
1 - cos²x = cos²x + 2cos x + 1
Collect like terms
1-1-cos²x-cos²x-2cos x = 0
-2cos²x-2cos x = 0
-2cos²x = 2cos x
-cosx = 1
cos x = -1
x = arccos -1
x = 180 degrees
<em>Hence the value of x = π</em>
