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Arada [10]
3 years ago
11

Football teams toss a coin to see who will get their choice of kicking or receiving to begin a game. the probability that given

team will lose the toss three games in a row is 0.125.
a. True
b. False
Mathematics
2 answers:
Tpy6a [65]3 years ago
8 0

Answer:

a. True

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either the team loses, or it wins. The probability of the team winning the coin toss in a game is independent of any other game. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Equally as likely to win or loss the coin toss(heads or tails).

So p = 0.5.

Three games

So n = 3

We have to find P(X = 0). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.5)^{0}.(0.5)^{3} = 0.125

So the answer is true.

Artist 52 [7]3 years ago
7 0

In a toss coin, the only result is a head or a tails. Therefore that ½ of the time you can win or ½ of the time you can lose. Therefore the probability of losing three games in a row is:

<span>P = (1/2) * (1/2) * (1/2)
P = 0.125</span>

<span>Therefore the answer is “True”.</span>

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