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hodyreva [135]
3 years ago
6

28 points asap pls PLSSS

Mathematics
2 answers:
Gennadij [26K]3 years ago
6 0

Answer:

Its answer is Commutative property

saw5 [17]3 years ago
5 0

Step-by-step explanation:

Answer will be Commutative property

hope it helps

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Kana bikes 22 miles in 2 hours her sister Emiko bikes 48 miles in 4 hours.
borishaifa [10]

Answer:

The answer is 11 miles an hour for kana and 12 miles and hour

Step-by-step explanation:

7 0
3 years ago
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Which two statements are missing in steps 3 and 4? ∠X ≅ ∠C △ABC ~ △ZYX by the SAS similarity theorem. ∠B ≅ ∠Y △ABC ~ △ZYX by the
Zepler [3.9K]

Solution:

We have to prove that ,

△ABC ~ △Z Y X   Using SAS.

It is given that , ∠X ≅ ∠C .

You must keep in mind when two triangles are similar by S A S

1. The included side between the angle should be Proportional.

   \frac{BC}{XY}=\frac{AC}{XZ}

2. We have to prove that ,

△ABC ~ △Z Y X   Using SAS.

It is given that , ∠B ≅ ∠Y .

The included side between the given angle should be Proportional.

   \frac{BA}{ZY}=\frac{BC}{XY}

3. We have to prove that ,

△ABC ~ △Z Y X   Using SSS.

The three sides of two triangles must be Proportional.

   \frac{BC}{XY}=\frac{AB}{ZY}=\frac{AC}{XZ}

7 0
3 years ago
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Simplifying rational expressions <br> x^2-16/x^2+6x+8 = x-4/x+2<br> x^2-x-6/x^2-3x-10 = x-3/x-5
enot [183]

1)

\dfrac{x^2-16}{x^2+6x+8}

Decompose the numerator and denominator into multipliers

To simplify the numerator we use the formula of difference of squares

x^2-y^2=(x-y)(x+y)

x^2-16=(x-4)(x+4)

To decompose the denominator into multipliers solve the square equation

x^2+6x+8=0\\D=6^2-4*8=4=2^2\\x_1=\dfrac{-6+2}{2} =-2\\x_2=\dfrac{-6-2}{2} =-4

Formula for factoring a square equation

(x-x_1)(x-x_2)

Substituting the found roots of the equation into the formula

(x-(-2))(x-(-4))=(x+2)(x+4)

After simplifying the numerator and denominator we get a fraction

\dfrac{(x-4)(x+4)}{(x+2)(x+4)}=\dfrac{x-4}{x+2}, so

\dfrac{x^2-16}{x^2+6x+8}=\dfrac{(x-4)(x+4)}{(x+2)(x+4)}=\dfrac{x-4}{x+2}

2)

\dfrac{x^2-x-6}{x^2-3x-10}

Decompose the numerator and denominator into multipliers

To decompose the numerator into multipliers solve the square equation

x^2-x-6=0\\D=(-1)^2-4*(-6)=25=5^2\\x_1=\dfrac{1+5}{2} =3\\x_2=\dfrac{1-5}{2} =-2

Formula for factoring a square equation

(x-x_1)(x-x_2)

Substituting the found roots of the equation into the formula

(x-3)(x-(-2))=(x-3)(x+2)

To decompose the denominator into multipliers solve the square equation

x^2-3x-10=0\\D=(-3)^2-4*(-10)=49=7^2\\x_1=\dfrac{3+7}{2} =5\\x_2=\dfrac{3-7}{2} =-2

Formula for factoring a square equation

(x-x_1)(x-x_2)

Substituting the found roots of the equation into the formula

(x-5)(x-(-(-2))=(x-5)(x+2)

After simplifying the numerator and denominator we get a fraction

\dfrac{(x-3)(x+2)}{(x-5)(x+2)}=\dfrac{x-3}{x-5}, so

\dfrac{x^2-x-6}{x^2-3x-10}=\dfrac{(x-3)(x+2)}{(x-5)(x+2)}=\dfrac{x-3}{x-5}

Hello from Russia:^)

6 0
3 years ago
2x −3 y = 21 hmu wit da answer
bazaltina [42]

slope is 2/3 and y intercept is 7

5 0
3 years ago
I have no idea what this means pls help
Anastaziya [24]
It’s the 3rd answer trust me
6 0
3 years ago
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