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3 years ago

Round 101 to the nearest ten

Mathematics

2 answers:

DENIUS [597]3 years ago

6 0

100 is 101 to the nearest ten

Orlov [11]3 years ago

4 0

To round 101 to the nearest 10, we first need to locate the tens place, which holds the value 0. Now, we basically need to round to 10 or to 0. To do this, we look at the one's place, which holds the value 1. One is closer to 0 than 10, so we round down, which gives us a final answer of 100. Hope this helps and have a fabulous day!

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-8z+(4.5)+3.5z+7y-1.5

bogdanovich [222]

Answer:

$\boxed{\sf{7y+3-4.5z}}$

Step-by-step explanation:

In order to combine like terms, you have to isolate x and y from one side of the equation.

$\sf{-8z+\left(4.5\right)+3.5z+7y-1.5}$

First, thing you do is remove parentheses.

$\Longrightarrow: \sf{-8z+4.5+3.5z+7y-1.5}$

Solve.

Then, you combine like terms.

$\Longrightarrow:\sf{-8z+3.5z+7y+4.5-1.5}$

Add/subtract the numbers from left to right.

-8z+3.5z=-4.5z

Rewrite the problem down.

$\Longrightarrow: \sf{-4.5z+7y+4.5-1.5}$

Solve.

4.5-1.5=3

$\Longrightarrow: \boxed{\sf{7y+3-4.5z}}$

Therefore, the correct answer is 7y+3-4.5z.

I hope this helps, let me know if you have any questions.

6 0

1 year ago

Which is the value of this expression when m=3 and n=-5? (6m^-1 n^0)^-3

iragen [17]

Answer:

The answer is C.

Step-by-step explanation:

I would simplify the expression first.

Equation: (6m^-1)^-3

You can get rid of n^0 because that equals 1.

Any expression raised to the power of -1 equals its reciprocal.

Equation: (6/m)^-3

Equation: (m/6)^3

Final Equation: m^3/216

Now, plug in 3.

(3)^3/216.

27/216 = 1/8

Hope this helps!

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Zolol [24]

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Answer:

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