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Margarita [4]
3 years ago
5

Can someone Solve this math problem for me I'm having some trouble.27×26+98÷25?​

Mathematics
2 answers:
AlladinOne [14]3 years ago
5 0

Answer:

<u>7</u><u>0</u><u>5</u><u>.</u><u>9</u><u>2</u><u> </u>

Step-by-step explanation:

hope it's help

#MASTER GROUP

# FIRST MASTER

<u>#</u><u> </u><u>PHILIPPINES</u>

RUDIKE [14]3 years ago
4 0

Answer:

705.92is the correct answer

Step-by-step explanation:

i

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HELP!!!!!! What is the equation of the axis of symmetry for the parabola ​
Dima020 [189]

Answer:

The line of symmetry is x = 3

Step-by-step explanation:

To find the line of symmetry in this case, use the base formula for vertex form.

y = a(x - h) + k

In this formula, h is the line of symmetry. In this case, h is 3.

3 0
3 years ago
Could someone help me with this? Please No guessing! Explain how you got the answer! And make sure your answer is correct! :) th
stealth61 [152]

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The numbers on the left represent 10 times that number

The numbers on the right are added to the end of the number on the left so

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4 0
3 years ago
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
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Zepler [3.9K]
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3 years ago
1. The degree of the polynomial is - even or odd
kondaur [170]
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