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lora16 [44]
3 years ago
9

Write the equation of the line that passes through (5,-7) and (0, -1)

Mathematics
2 answers:
weeeeeb [17]3 years ago
7 0

Equation of a line can be given by :

y = mx + b

Let's find the slope of the line (m) :

\mathcal{ \hookrightarrow \:   \dfrac{y_2 - y_1}{x_2 - x_1} }

\mathcal{ \hookrightarrow \:   \dfrac{ - 1 - ( - 7)}{0 - 5} }

\hookrightarrow \:  \dfrac{6}{ - 5}

\hookrightarrow \:  m = \dfrac{ - 6}{5}

now let's solve for b :

\hookrightarrow \: y = mx + b

Let's plug the values of x and y from the coordinates of a point .

\hookrightarrow \:  - 7 =   (\dfrac{ - 6}{5}  \times 5) + b

\hookrightarrow \:  - 7 =  - 6 + b

\hookrightarrow \: b =  - 1

now, let's put the value of m (slope) and b (y-intercept) in the equation.

\hookrightarrow \: y = mx + b

\boxed{  \boxed{\: y =  \dfrac{ - 6}{5}x - 1 }}

That's All, I hope it helped ya

Fiesta28 [93]3 years ago
3 0

4,3,2,1,0,-1, -2, -3, -4,

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