All categories

3 years ago

12 = -4(-6x -3) +24

Mathematics

1 answer:

Reil [10]3 years ago

8 0

Answer:

x = -1

Step-by-step explanation:

Solve for x:

12 = 24 - 4 (-6 x - 3)

-4 (-6 x - 3) = 24 x + 12:

12 = 24 x + 12 + 24

Grouping like terms, 24 x + 12 + 24 = 24 x + (12 + 24):

12 = 24 x + (12 + 24)

12 + 24 = 36:

12 = 24 x + 36

12 = 24 x + 36 is equivalent to 24 x + 36 = 12:

24 x + 36 = 12

Subtract 36 from both sides:

24 x + (36 - 36) = 12 - 36

36 - 36 = 0:

24 x = 12 - 36

12 - 36 = -24:

24 x = -24

Divide both sides of 24 x = -24 by 24:

(24 x)/24 = (-24)/24

24/24 = 1:

x = (-24)/24

The gcd of -24 and 24 is 24, so (-24)/24 = (24 (-1))/(24×1) = 24/24×-1 = -1:

Answer: x = -1

You might be interested in

How many angles is in a hexagon

andrezito [222]

A hexagon has Six sides

8 0

3 years ago

Read 2 more answers

5. Adam spent half of his weekly allowance buying lunch. To earn

Gekata [30.6K]

Answer: $11.60

Explanation: First, you want to do 15.1 - 9.3 to find what half of his weekly allowance is, and that would be 5.8, AKA $5.80. Next, you want to multiply that number by 2, which would be 5.8(2) to get 11.6, or your final answer, $11.60.

3 0

3 years ago

1 - 5/6 < 3x + 5/6 -2x

Romashka-Z-Leto [24]

Answer:

−2

Step-by-step explanation:

6 0

3 years ago

Tomas factored the polynomial completely. What is true about his final product? 3x4−18x3+9x2−54x Ax(x2+B)(x+C)

iren2701 [21]

Answer:

A and B are both 3.

Step-by-step explanation:

The given polynomial is $3x^4-18x^3+9x^2-54x$ .

We factor the GCF to obtain:

$3x(x^3-6x^2+3x-18)$

We factor further by grouping to get:

$3x[x^2(x-6)+3(x-6)]$

$3x(x^2+3)(x-6)$

We compare this to the given factored expression:

$3x(x^2+3)(x-6)=Ax(x^2+B)(x+C)$

We must have A=3,B=3, C=-6

8 0

3 years ago

Read 2 more answers

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago