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3 years ago

There are 1,468 students at Lakeside

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

Answer:

I think that the answer is 3 312

Step-by-step explanation:

1468 +376= 1844 ,the total number of students at the Oak school.

1844 + 1468=3 312, the total number of students at both schools

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The quotient of 12 and the opposite of 3 plus the product of the opposite of 14 and 4

Fynjy0 [20]

Putting this into an equation, it would be (12 ÷ -3) + - (14 x 4)
-4 + -56 = -60

4 0

3 years ago

Read 2 more answers

Six times a number is greater than 20 more than that number what are the possible values of that number

Degger [83]

Let n = the unknown number.

Six times a number = 6 * n = 6n

20 more than number = n + 20

Greater than = >

Put it all together:

6n > n + 20

Subtract n from both sides to get constants on one side and variables on the other:

6n - n > 20

5n > 20

Divide both sides by 5 to isolate variable N

n > 4

or (4, ∞)

4 0

3 years ago

What is the radius of the circle? Hurrry

goldenfox [79]

Answer:

8 in

Step-by-step explanation:

Given,

Diameter ( circle ) = 16 in ( from the diagram )

To find : Radius ( circle ) = ?

Formula : -

Radius ( circle ) = Diameter ( circle ) / 2

Radius ( circle )

= 16 / 2

= 8 in

5 0

3 years ago

The answer is going to be 4

NISA [10]

Answer:

Step-by-step explanation:

you said the answers going to be 4

3 0

3 years ago

Read 2 more answers

This Venn diagram shows the pizza topping preferences for 9 students. Let event A = The student likes pepperoni. Let event B = T

victus00 [196]

Answer:

$P(A\ or\ B)=\frac{7}{9}$

Step-by-step explanation:

We need to use the formula to calculate the probability of (A or B) where

A=Probability a student likes pepperoni

B=Probability a student likes olive

A and B =Probability a student likes both toppings in a pizza

A or B =Probability a student likes pepperoni or olive (and maybe both), a non-exclusive or

The formula is

$P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$

Since 6 students like pepperoni out of 9:

$P(A) = \frac{6}{9}$

Since 4 students like olive out of 9:

$P(B) = \frac{4}{9}$

Since 3 students like both toppings out of 9

$P(A\ and\ B) = \frac{3}{9}$

Then we have

$P(A\ or\ B)=\frac{6}{9}+\frac{4}{9}-\frac{3}{9}$

$P(A\ or\ B)=\frac{7}{9}$

7 0

3 years ago