Answer:
p = 2
n = 14
m = 3
Step-by-step explanation:
In order to be able combine (either add or subtract) rational expressions we need to write them with a common (similar) denominator. For that reason we first find the Least Common Denominator of both fractions, that way understanding how to express the two fractions using equivalent fractions with like denominator that can be combined.
We see that the denominator of the first fraction contains the factor "x", therefore "x" has to be a factor of that least common denominator.
We also see that the second fraction contains "2" as a factor, therefore 2 has to be a factor as well for our Least Common Denominator (LCD)
So the LCD we need is the product: 2*x which we write as 2x.
Now we write the first fraction as an equivalent one but with denominator "2x" by multiplying top and bottom by 2 (and thus not changing the actual value of the fraction): 
Next we do the same with the second fraction, this time multiplying top and bottom by the factor "x":
Now that both fractions are written showing the same denominator , we can combine them as indicated:
This expression gives as then the values for the requested coefficients.
p = 2
n = 14
m = 3
Answer:
I believe it would be answer 2)
Step-by-step explanation:
The team has 4 players and the line graph starts at 5 increasing to 9
About 1.19 %
80*1.19= 95.2 Since 2 is not 5 or above it get knocks down to 95 exactly
First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.
We have
130 = 2 • 5 • 13
231 = 3 • 7 • 11
so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.
To verify the claim, we try to solve the system of congruences
Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:
130 = 7 • 17 + 11
17 = 1 • 11 + 6
11 = 1 • 6 + 5
6 = 1 • 5 + 1
⇒ 1 = 23 • 17 - 3 • 130
Then
23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)
so that x = 23.
Repeat for 231 and 17:
231 = 13 • 17 + 10
17 = 1 • 10 + 7
10 = 1 • 7 + 3
7 = 2 • 3 + 1
⇒ 1 = 68 • 17 - 5 • 231
Then
68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)
so that y = 68.
The sides of a right triangle can always be expressed as:
h^2=x^2+y^2, where h is the length of the hypotenuse and x and y are the side lengths.
If we are to assume that "a" is a side length then 17 or "c" must be the hypotenuse so:
17^2=11^2+a^2
a^2=289-121
a^2=168
a=√168
a≈12.96 (to nearest hundredth)
Note we knew this assumption because of the answer choices, but technically, "a" COULD have been the hypotenuse without this implicit suggestion making:
a^2=17^2+11^2
a^2=410
a=√410
a≈20.25 (to the nearest hundredth)
Of course the above is not relevant to this particular question but be aware that you won't always be given answer choices to make the assumption of which side is the hypotenuse...
