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IgorLugansk [536]

2 years ago

9

I WILL MARK AS BRAINLIEST! Solve for X and Y

2 answers:

deff fn [24]2 years ago

8 0

Answer:

Move all terms that don't contain x to the right side and solve.

<h3>Question 5</h3>

<u>Don't forget to replace all y's with a -8!</u>

a) x = 32

b) x = 12

c) x = 33

d) Exact Form: x = 36/5

Decimal Form: x = 7.2

Mixed Number Form: x = 7 1/5

<h3>Question 6</h3>

<u>Don't forget to replace all x's with a 0!</u>

a) y = 93

b) y = -95

c) y = -87

d) y = -81

I hope this answer was helpful!

konstantin123 [22]2 years ago

5 0

Answer:

1.

a) 40 b) 8 c) 27 2/3 d) 4

2.

a) 93 b) -95 c) -87 d) -81

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One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W

Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P( $\text{B}_1$ ) = 0.2, P( $\text{B}_2$ ) = 0.4, P( $\text{B}_3$ ) = 0.3, P( $\text{B}_4$ ) = 0.6, P( $\text{B}_5$ ) = 0.5.

So, the probability that the cell will be killed is given by;

P(A)= $1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]$

P(A) = $1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]$

P(A) = $1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)$

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

4 0

3 years ago

a rain gutter is to be installed around a house whose Foundation is shown to the right find the perimeter of the house then find

Alexus [3.1K]

The perimeter is 96 feet, and 96 X 4.77 = is 457.92

5 0

2 years ago

There is a bag filled with 2 blue, 4 red and 5 green marbles.

Vinil7 [7]

<h3>Answer: 45/121</h3>

=========================================

Work Shown:

2 blue, 4 red, 5 green

2+4+5 = 11 total

P(blue) = probability of getting one blue marble

P(blue) = (number of blue)/(number total)

P(blue) = 2/11

A = P(2 blue) = (2/11)*(2/11) = 4/121

P(red) = 4/11

B = P(2 red) = (4/11)*(4/11) = 16/121

P(green) = 5/11

C = P(2 green) = (5/11)*(5/11) = 25/121

Add the values of A,B, and C to get the probability of getting two of the same color

A+B+C = 4/121+16/121+25/121 = 45/121

This is approximately equal to 0.3719 which is roughly a 37.19% chance of happening

Side note: we can add A,B, and C because they are mutually exclusive events.

6 0

3 years ago

Find the highest common factor of 63 and 81 please no links

Zielflug [23.3K]

The answer is 9 it’s the most common

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2 years ago

In ΔNOP, p = 38 cm, n = 13 cm and ∠O=152°. Find the area of ΔNOP, to the nearest square centimeter.

Vika [28.1K]

Answer:

Step-by-step explanation:

Answer-116

3 0

2 years ago