You have
.. f'(u) = sec(u)^2
Putting in u = g(x) = x^9, this becomes
.. f'(g(x)) = sec(x^9)^2
You know
(f(g(x))' = f'(g(x))*g'(x) . . . . . chain rule
From previous results, this is
.. sec(x^9)^2*9x^8
Answer:
B) 2/3=x/4
Step-by-step explanation:
Since the figures are similar, we can use ratios to solve
2 x
----- = -----------
3 4
Answer: yes.
Step-by-step explanation:
Answer:
The interquartile range is 10.
Step-by-step explanation:
(xu-xl)=10
First, we have to solve the sides of the right triangle by using the Pythagorean theorem: a² + b² = c² where c is the length of the hypotenuse. Then, we can use the legs as length and height of the triangle and find the area by 1/2(base x height).
x² + 60² = 68²
x² + 3600 = 4624
x² = 1024
x = √1024
x = 32 = length of the other side
A = (1/2)(32) (60) = 960 mm²
