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alina1380 [7]
3 years ago
14

Is Canada‘s population is 1/10 of the United States and Canada‘s population is 32 million how many people live in the United Sta

tes
Mathematics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

320M

Step-by-step explanation:

It is given that Canada's population is 1/10th of the USA's population, essentially meaning that the US's population is 10x that of Canada's. Therefore, if Canada's population is 32M, multiply 10 to that:

32,000,000 x 10 = 320,000,000

320,000,000 people live in the US.

~

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Answer:

Its 8/33. Hope this helps.

Step-by-step explanation:

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A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11. Use the TI-84 Plus calculator. (a) I
sukhopar [10]

Answer:

a) We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

b) There is a 15.97% probability that x will be between 54 and 55.

c) The 47th percentile of x is X = 52.877.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11.

This means that \mu = 53.

We have to find the standard deviation of the sample, that is:

\sigma = \frac{11}{\sqrt{45}} = 1.64

(a) Is it appropriate to use the normal distribution to find probabilities for x?

We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

(b) Find the probability that x will be between 54 and 55.

This is the pvalue of the Z score when X = 55 subtracted by the pvalue of the Z score when X = 54.

X = 55

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 53}{1.64}

Z = 1.22

Z = 1.22 has a pvalue of 0.88877.

X = 54

Z = \frac{X - \mu}{\sigma}

Z = \frac{54 - 53}{1.64}

Z = 0.61

Z = 0.61 has a pvalue of 0.72907.

So, there is a 0.88877 - 0.72907 = 0.1597 = 15.97% probability that x will be between 54 and 55.

(c) Find the 47th percentile of x. Round the answer to at least two decimal places.

This is the value of X when Z has a pvalue of 0.47;

This is between Z = -0.07 and Z = -0.08. So we use Z = -0.075.

Z = \frac{X - \mu}{\sigma}

-0.075 = \frac{X - 53}{1.64}

X = 52.877

The 47th percentile of x is X = 52.877.

8 0
3 years ago
Expand and simplify (3x+5)(4x-1)
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Use FOIL and simply, First times First, Outside times Outside, Inside times Inside, Last times Last.

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Now simplify by adding -3x to 20x and get:

12x² + 17x - 5
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