√((25x^9y^3)/(64x^6y^11)) doing the normal division within the radical
√((25x^3)/(64y^8) then looking at the squares within the radical...
√((5^2*x^2*x)/(8^2*y^8)) now we can move out the perfect squares...
(5x/(8y^4))√x
So it is the bottom answer...
Subtract the y values to one side then the numbers to the other so as x values to one side then the numbers to the other
Answer:
no solution
Step-by-step explanation:
-9x +5 < 17 AND 13x + 25 < -1
Solve each part separately and then put back together
-9x +5 < 17
Subtract 5 from each side
-9x+5-5< 17-5
-9x < 12
Divide each side by -9 remembering to flip the inequality
-9x/-9>12/-9
x > -4/3
and
13x + 25 < -1
subtract 25 from each side
13x +25-25 < -1-25
13x <-26
Divide by 13
13x/13 < -26/13
x <-2
There is no overlap so there is no solution
3 sig figs in the final answer since the denominator has 3 sig figs. So the answer would be 4.05
Answer:
6. c. 120
7. $6.45
Step-by-step explanation:
1. 150 x 0.20 = 30
2. 150- 30= 120
1. 43 x 0.15= 6.45