aleta's puppy gained 3/8 pounds each week for 4 weeks. altogether, how much weight did the puppy gained

I need help with #9 please

zepelin [54]

The median would decrease because the temperature given is lower than the median

5 0

3 years ago

Simplify x + 3x – 36.

Doss [256]

X + 3x - 36.....x is the same as 1x....combine like terms
1x + 3x - 36 = 4x - 36 <==

8 0

3 years ago

Read 2 more answers

Find percentage of each quantity. 40% of an hour In hours and minutes

matrenka [14]

Answer:

Step-by-step explanation:

40% of an hr.....an hr is 60 minutes...so 40% of 60 minutes =

0.4(60) = 24 minutes

8 0

4 years ago

In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time coll

algol13

Answer:

(a) The sample size required is 2401.

(b) The sample size required is 2377.

(c) Yes, on increasing the proportion value the sample size decreased.

Step-by-step explanation:

The confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hatp(1-\hat p)}{n}}$

The margin of error in this interval is:

$MOE=z_{\alpha/2}\sqrt{\frac{\hatp(1-\hat p)}{n}}$

The information provided is:

MOE = 0.02

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

(a)

Assume that the proportion value is 0.50.

Compute the value of n as follows:

$MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\n=\frac{1.96^{2}\times0.50(1-0.50)}{0.02^{2}}\\=2401$

Thus, the sample size required is 2401.

(b)

Given that the proportion value is 0.55.

Compute the value of n as follows:

$MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.55(1-0.55)}{n}}\\n=\frac{1.96^{2}\times0.55(1-0.55)}{0.02^{2}}\\=2376.99\\\approx2377$

Thus, the sample size required is 2377.

(c)

On increasing the proportion value the sample size decreased.

8 0

4 years ago

The pressure at sea level is 11 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of

Taya2010 [7]

Answer:

p(x) = 0.1x + 1

Step-by-step explanation:

Pressure at sea level = 1 atmosphere

Depth dove by Sydney = 23 meters

Pressure at a depth of 23 meters = 3.3 atmospheres

So,

Pressure at a depth of 23 meters = Pressure at sea level + k * Depth dove by Sydney

where k is the diving rate constant

=> 3.3 = 1 + k(23)

=> 3.3 = 23k + 1

Subtracting 1 from both the sides, we get

3.3 - 1 = 23k + 1 -1

Cancelling out the +1 and -1 from the right side, we get

2.3 = 23k

=> 23k = 2.3

Dividing both sides by 23, we get

$\frac{23k}{23} = \frac{2.3}{23}$

Cancelling out the 23's from the top and bottom of the left side, we have

k = 0.1

Plugging in the value of k in the equation, we get

Pressure at a particular depth = Pressure at sea level + k * Depth dove by Sydney

p(x) = 1 + k(x) [where p(x) is the pressure at a depth x]

=> p(x) = 1 + 0.1(x)

=> p(x) = 0.1x + 1

5 0

3 years ago