Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x? StartFraction 5 plus-or-minus 3 StartRoot 11 EndRoo
t Over 12 EndFraction StartFraction 5 plus-or-minus StartRoot 97 EndRoot Over 12 EndFraction StartFraction 5 plus-or-minus StartRoot 47 EndRoot Over 12 EndFraction StartFraction negative 5 plus-or-minus StartRoot 97 EndRoot Over 12 EndFraction
2 answers:
Answer:
Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?
5x = 6x^2 – 3
Subtract 5x from both sides:
0 = 6x^2 – 5x – 3
a = 6, b = -5, c = -3
x = (-b ± √(b^2 - 4ac))/(2a)
x = (-(-5) ± √((-5)^2 - 4(6)(-3)))/(2(6))
x = (5 ± √(25 + 72))/12
x = (5 ± √(97))/12
Step-by-step explanation:
Answer:
your answer is C
Step-by-step explanation:
thank me later;)
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