Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x? StartFraction 5 plus-or-minus 3 StartRoot 11 EndRoo
t Over 12 EndFraction StartFraction 5 plus-or-minus StartRoot 97 EndRoot Over 12 EndFraction StartFraction 5 plus-or-minus StartRoot 47 EndRoot Over 12 EndFraction StartFraction negative 5 plus-or-minus StartRoot 97 EndRoot Over 12 EndFraction
2 answers:
Answer:
Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?
5x = 6x^2 – 3
Subtract 5x from both sides:
0 = 6x^2 – 5x – 3
a = 6, b = -5, c = -3
x = (-b ± √(b^2 - 4ac))/(2a)
x = (-(-5) ± √((-5)^2 - 4(6)(-3)))/(2(6))
x = (5 ± √(25 + 72))/12
x = (5 ± √(97))/12
Step-by-step explanation:
Answer:
your answer is C
Step-by-step explanation:
thank me later;)
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Answer:
x = 2
Step-by-step explanation:
2x - 10 + 3x - 15 = 10
5x - 25 = 10
5x = 35
x = 7
7 - 5 = 2
Answer:
y = 8.1
Step-by-step explanation:
y+2.9=11
Subtract 2.9 from each side
y+2.9-2.9 = 11-2.9
y =8.1
7/10x - 5 = 1/2x
7/10x - 1/2x = 5
7/10x - 5/10x = 5
2/10x = 5
x = 5 / (2/10)
x = 5 * 10/2
x = 50/2
x = 25 gallons <===
When you don't use or write the percent right.<span />
Answer:
yes the sides of a triangle can have all those sides
