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Umnica [9.8K]
3 years ago
9

Write the taylor series for f(x)=sin(x) at x=π2

Mathematics
1 answer:
Kay [80]3 years ago
3 0
Try to see on Google for solutions like that

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<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
Find the derivative of f(t)=2√t - 2/√t
Semmy [17]
The answer is t=1.

Hope this helps.
8 0
3 years ago
Read 2 more answers
Let f(x)= x2 - 14 and g(x) = 6-X.<br> Find (fq)(7).
sleet_krkn [62]

Answer:

(fg)(7) = - 35

Step-by-step explanation:

The given functions are:

f(x) =  {x}^{2}  - 14

and

g(x) = 6 - x

We want to to find

(fg)(7)

Note that:

(fg)(x) = f(x) \times g(x)

We substitute the functions to obtain:

(fg)(x) = ( {x}^{2} -1 4 ) \times (6 - x)

We now substitute x=7, to get:

(fg)(7) = ( {7}^{2} -1 4 ) \times (6 - 7)

This implies that

(fg)(7) =( 49-1 4 ) \times (6 - 7)

(fg)(7)  = 35 \times  - 1 =  - 35

8 0
3 years ago
Is it pp PP pP or coc
ddd [48]

Answer:

its Pp or it could also be nonexistent

8 0
3 years ago
If y=−3, then 4y/4+y = ?
Charra [1.4K]

Answer:

If y=−3,

then

4y/4+y

=4×(-3)/4+(-3)

= -12/1

= -12 ,,

6 0
3 years ago
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