Answer:
b = 80
Step-by-step explanation:
Given that,
x² + bx - 81
To find,
value of b
What is factorable?
A polynomial equation with highest degree 2 is if factorable when
- we can find two terms which when multiples = -81x², <em> ( x² * - 81 = -81x² ) </em>
- and when add = bx
possible factors:
- -1x * 81x = -81x² (Accepted)
- 1x * -81x= -81x² (rejected)
- 9x * -9x = -81x² (rejected)
- -9x * 9x = -81x² (rejected)
Only when -1x , 81x is added -1x + 81x = 80x
so, bx = 80x
b = 80
<h3>The equation is x² + 80x - 81</h3>
Answer:
-3x + 9
Explanation:
Because these two integers that is - and - is said to be added and write the sign of of greater or bigger number.
The future value of the amount deposited will be given by:
FV=p(1+r/100n)^nt
where:
FV=future value
p=principle
r=rate
n=terms
t=time
thus substituting our values in the formula we get:
FV=4000(1+5.4/1200)^(6×12)
FV=$5,526.57
Answer: $5,526.57
Answer:
E
Step-by-step explanation:
using the rule of radicals
× 
⇔ 
, hence
= 
= 
× 
× 
[ = i]
= 2i → E
This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).
