Answer:
x=37°
y=6
Step-by-step explanation:
(ASSUMING BD is a perpendicular bisector of AC, otherwise answers maybe be wrong)
Consider the triangle ABC:
AB is the same length as BC (marked), meaning ABC is an isosceles triangle.
Since ABC is isosceles, ∠BAC=∠BCA=53
All angles in a triangle add up to 180:
180=∠ABC + ∠BAC + ∠BCA
180= ∠ABC + 53 +53
∠ABC = 180 - 106
∠ABC = 74
Assuming BD bisects ∠ABC perfectly, x is half of ∠ABC.
x=74/2=37
If BD bisects AC perfectly, AD=DC=y=6
Isn't this a subtraction problem, not a multiplication problem?
If John starts out with 20 fish and lets 6 go, he still has (20-6), or 14, fish.
Answer:
-2pi/3
Step-by-step explanation:
y = 2 cos 3(x + 2π∕3) +1
y = A sin(B(x + C)) + D
amplitude is A
period is 2π/B
phase shift is C (positive is to the left)
vertical shift is D
We have a shift to the left of 2 pi /3
On an isosceles trapezoid, the two sides that are not parallel to each other will be exactly the same length. If this is true, than it would be create a symetric trapezoid. The diagonals would be the same length. The bases of any trapezoid are parallel, so this is true. The diagonals cannot possibly be perpendicular because the 2 nonparallel sides would be slanted. So, the answer is the 3rd choice.
