Answer:
a) Is it possible for Fred to accomplish this? Yes
b) If it is possible, what score does he need in his next game? 293
Step-by-step explanation:
Step 1
Let us represent the number of games Fred bowled to get an average of 177 = X
His total points scored in that game would be
177 × X
= 177X
To achieve an average of 178 for his next game,
The total number of points he scored was 199, hence that is represented as:
178 = 177X + 199/ X + 1
178(X + 1) = 177X + 199
178X + 178 = 177X + 199
178X - 177X = 199 - 178
X = 21
Hence, Fred bowled 21 games to achieve an average of 178
Therefore, the score he needs to have on the 23rd game is obtained as:
= (23 × 183) - (22 × 178) = 4209 - 3916 = 293
Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.
Examples of this are:
2 and 
2 and 
4 and 
I'm guessing you have a work sheet going along with this which has actual images of containers. I've attached an example - if you can post the actual work sheet you're referring to I can edit this answer to correctly reflect your specific question.
Answer:
a. 3.9714285714 b.1.404040404
Step-by-step explanation:
13.9/3.5
13.9/9.9
I do not know if this is correct, but give it a try.
Answer: 157.5
Step-by-step explanation: To get the volume of an object you must multiply the width x height ÷ it by 2 x length
Therefore 7 x 5 = 35 ÷ 2 = 17.5
17.5 x 9 = 157.5
We can write the equation: x + x + 2 + x + 4 = -48, where x is the least digit and x + 4 is the greatest. We get 3x + 6 = -48, 3x = -54. x = -18, so x + 2 is -20, and x + 4 is -22. Therefore, the 3 consecutive even integers that sum to -48 are -18, -20, and -22.
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Hope this helps!
