Question

sketch the curve represented by the parametric equations (indicate the orientation of the curve), write the corresponding rectangular equation by eliminating the parameter.x=3t-5 y=5t+1

Answer 1

Answer:

Reduced equaton is $5x-3y+\frac{28}{3}=0$.

Step-by-step explanation:

Given parametric equation is,

$x=3t-5$ and $y=5t+1$

Now, $x=3t-5\implies t=\frac{x+5}{3}$ substitute in second equation we get,

$y=\frac{5}{3}(x+5)+1$

$y=\frac{5}{3}x+\frac{28}{9}$

$\implies 5x-3y+\frac{28}{3}=0$

which is the corresponding rectangular equation after eliinating the parameter.

Now consider,

$y=\frac{5}{3}x+\frac{28}{9}$

Of which,

Slope : $\frac{5}{3}$

when,

$x=0, y=\frac{28}{9}=3.1$

$x=1, y=\frac{43}{9}=4.8; x=-1, y=\frac{13}{9}=1.4$

$x=2, y=\frac{58}{9}=6.4; x=-2, y=\frac{-2}{9}=-0.2$

$x=3, y=\frac{73}{9}=8.1; x=-3, y=\frac{-17}{9}=-1.8$

$x=4, y=\frac{88}{9}=9.8; x=-4, y=\frac{-32}{9}=-3.6$

$x=5, y=\frac{103}{9}=11.4; x=-5, y=\frac{-47}{9}=-5.2$

ans so on. Thus sketching th curve will look like given,