Find the length of BE BC=3x+47 DE=10 BD=x+27 CE=x+26

Mathematics

1 answer:

adoni [48]3 years ago

7 0

Answer:

B____C____D_____E

BC+ CE = BD + DE

(3x+47) + (x+26) = ( x+27) + (10)

4x + 73 = x + 37

4x – x = 37 – 73

3x = ‐ 36

x = – 36/ 3 —> x = – 12

BC = 3x + 47 = 3(-12) + 47 = - 36 + 47 = 11

BD = x+ 27 = –12+27 = 15

CE = x + 26 = –12+26= 14

I hope I helped you^_^

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<h3>What is a quadratic function?</h3>

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