Question

Find the length of BE BC=3x+47 DE=10 BD=x+27 CE=x+26

Answer 1

Answer:

B____C____D_____E

BC+ CE = BD + DE

(3x+47) + (x+26) = ( x+27) + (10)

4x + 73 = x + 37

4x – x = 37 – 73

3x = ‐ 36

x = – 36/ 3 —> x = – 12

BC = 3x + 47 = 3(-12) + 47 = - 36 + 47 = 11

BD = x+ 27 = –12+27 = 15

CE = x + 26 = –12+26= 14

So;

BE = BD+ DE = 15+ 10= 25

Or ;

BE= BC + CE = 11+ 14 = 25

I hope I helped you^_^