Answer:

Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean
kilograms and standard deviation
kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:

So then the corresponding z scale would be:

Answer:
UR MOM
Step-by-step explanation:
STIL YOUR MOM
<span>7N - 2N + 3P + 2P
Combine like terms:
7N-2N=5N
3P+2P=5P
Put them together to get :
5N+5P
Final answer:
A</span>
Answer:

Step-by-step explanation:
Hey mate !!
Here's your answer !!
2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0
2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0
Hence
2w - 3 = 0
2w = 3
w = 3/2
w - 4 = 0
w = 4
Hence value of w are 4 and 3/2
Hope this helps!!
Cheers!!