The interval notation is 
Explanation:
The inequality is 
Let us complete the square, we get,

Simplifying, we have,


Adding both sides of the equation by 11, we get,

Since, we know that for
, if n is even then ![-\sqrt[n]{a}](https://tex.z-dn.net/?f=-%5Csqrt%5Bn%5D%7Ba%7D%3Cu%3C%5Csqrt%5Bn%5D%7Ba%7D)
Thus, writing the above expression in this form, we get,

Also, if
then
and 
Then ,we have,
and 
Solving the inequalities, we get,
and 
Merging the intervals, we have,

Hence, writing the solution in interval notation, we have,

Therefore, the answer is 
1.36*10^7
where the 36 repeats so 36363636363636... and so on
Answer:
11 music lessons.
Step-by-step explanation:
We know that membership costs $165 and members pay $25 per music lesson.
So, we can write the following expression:

The 165 represents the one-time membership fee and the 25m represents the cost for m music lessons.
We know that non-members pay no membership fee but their cost per lesson is $40. So:

Represents the cost for non-members for m music lessons.
We want to find how many music lessons would have to be taken for the cost to be the same for both members and non-members. So, we can set the expressions equal to each other:

And solve for m. Let's subtract 25m from both sides:

Now, divide both sides by 15:

So, at the 11th music lesson, members and non-members will pay the same.
Further Notes:
This means that if a person would only like to take 10 or less lessons, the non-membership is best because there is no initial fee.
However, if a person would like to take 12 or more lessons, than the membership is best because the membership has a lower cost per lesson than the non-membership.
And we're done!
Im sorry buuuuuuuuuut um thats too small maybe zoom in.. ;/