The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
Step-by-step explanation:
Distribute into 5x² into (3x +2).
The simplified expression is <em>15x³ + 10x²</em>
Answer: 1.764
Step-by-step explanation:
<h2>Answer:</h2>
8.75 feet
<h2>
Step by step:</h2>
Given that a 12 foot ladder leans against a building seven feet above the ground.
By using trigonometry ratio, the angle between the ladder and the ground will be
SinØ = opposite/ hypothenus
SinØ = 7 / 12
SinØ = 0.58333
Ø = Sin^-1(0.58333)
Ø = 35.69 degree
At what height would an 15 foot ladder touch the building if both ladders form the same angle with the ground?
Using the same trigonometric ratios
SinØ = opposite/hypothenus
Sin 35.69 = opposite/ 15
Cross multiply
Opposite = 15 × sin 35.69
Opposite = 8.75 feet
Therefore, the ladder will touch the building if both ladders form the same angle with the ground at height 8.75 feet.
Answer:
0.4kg, 1.4kg and 1.8kg
Step-by-step explanation:
Given parameters:
Mass of alloy = 3.6kg
Ratio of elements in the alloy = 2:7:9
Unknown:
Mass of each element in the alloy = ?
Solution:
To find the mass of each element in the alloy, first find the sum of the ratio;
2+7+9 = 18
Mass of nickel = 
x 3.6 = 0.4kg
Mass of zinc = 
x 3.6 = 1.4kg
Mass of copper = 
x 3.6 = 1.8kg
The mass of each metal is 0.4kg, 1.4kg and 1.8kg
