Graph the equation. y=2x^2-8x+3y=2x 2 −8x+3
1 answer:
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Answer:
see attached
Step-by-step explanation:
The equation can be rewritten to vertex form, so you can tell the vertex is at (2, -5). The leading coefficient of 2 means the points will be twice as far apart vertically than they would be if the leading coefficient were 1. A couple of points are shown in the attached.
y = 2(x^2 -4x) +3
y = 2(x^2 -4x +4) +3 -8 . . . . . . complete the square
y = 2(x -2)^2 -5 . . . . . . . . . . . . finish putting in vertex form
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Answer:
We conclude that If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.
Step-by-step explanation:
If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.
For example, let the function
It is clear that the given function becomes undefined at x = 3 in the denominator.
i.e. 3-3 = 0
It means, the function can not have x = 3, otherwise, the function will become undefined.
In other words, if the function has a vertical asymptote at x = 3, then the function is undefined at the value.
Therefore, we conclude that If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.