Answer:
The maximum value of the table t(x) has a greater maximum value that the graph g(x)
Step-by-step explanation:
The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.
The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).
The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...
the maximum value of t(x) is greater than the maximum value of g(x)
Answer:
Taking P(x) = x³-12x-16 as an example
Step-by-step explanation:
For a polynomial, if
x = a is a zero of the function, then (x − a) is a factor of the function.
We have two unique zeros:
−2 and 4. However, −2 has a multiplicity of 2, which means that the factor that correlates to a zero of −2 is represented in the polynomial twice.
Following how it's constructed
zero at -2, multiplicity 2
zero at 4, multiplicity 1
p(x)=x−(−2))²(x−4)¹
Thus,p(x)=(x+2)²(x−4)
Expand: p(x)=(x²+4x+4)(x−4)
p(x) =x³−12x−16
