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3 years ago

11

7th grade math help me plzzzzz

1 answer:

Lady bird [3.3K]3 years ago

5 0

Answer:

94

Step-by-step explanation:

You might be interested in

How can you find this distance (-3,7),(0,4) in words

Bezzdna [24]

Answer:

The distance between these two given points is:

$3\sqrt{2}$

Step-by-step explanation:

We are given two points:

(-3,7),(0,4)

<em>The distance between two points (a,b) and (c,d) is given by the distance formula as:</em>

<em> $\sqrt{(c-a)^2+(d-b)^2$ </em>

similarly we can find the length of a line segment by considering the distance between the end points of the line segment.

So here (a,b)=(-3,7)

and (c,d)=(0,4).

Hence distance between these two points is given by:

$\sqrt{(0-(-3))^2+(4-7)^2}=\sqrt{(3)^2+(-3)^2}=\sqrt{9+9}\\ \\=\sqrt{18} \\\\=3\sqrt{2}$

6 0

3 years ago

Read 2 more answers

Y=2/7x-7 in standard form

ExtremeBDS [4]

Alright here it is:

-2/7x + y = -7

4 0

3 years ago

19. When baking a cake, you have a choice of the following pans:

dimaraw [331]

The answer is

round cake - 82.42 in²

rectangular cake - 114 in²

Round cake:

d = 7 in

r = d/2 = 7 in / 2 = 3.5 in

h = 2 in

The surface are of a cylinder is:

A = 2πr² + 2πrh

The surface are of the round cake (which is actually a cylindrical cake) excluding the bottom is:

A = 2πr² + 2πrh - πr²

A = πr² + 2πrh

A = 3.14 * 3.5² + 2 * 3.14 * 3.5 * 2

= 38.46 + 43.96

= 82.42 in²

Rectangular cake:

w = 6 in

l = 9 in

h = 2 in

The surface are of a rectangle is:

A = 2wl + 2wh + 2lh

The surface are of the rectangular cake excluding the bottom is:

A = 2wl + 2wh + 2lh - wl

A = wl + 2wh + 2lh

A = 6 * 9 + 2 * 6 * 2 + 2 * 9 * 2

= 54 + 24 + 36

= 114 in²

Step-by-step explanation: This answer is not mine but JcAlmighty’s so all credits go to them.

7 0

3 years ago

Read 2 more answers

Simplify this expression.<br><br> 20.25 –9 1/2+ 11<br><br> Pls help

grigory [225]

Answer:

The answer is -0.25.

Step-by-step explanation:

Using PEMDAS, add 9.5 + 11 first, which results in 20.5. Then substract 20.5 from 20.25, 20.25 - 20.5. This leads to -0.25 or -1/4.

7 0

3 years ago

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

3 years ago