Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS
Answer:
Domain: 
Range: 
Step-by-step explanation:
The domain of a function is the set of values that one can input into a function and get a valid result.
The range of a function is the set of valid outputs that one can attain when a value is substituted into a function.
PART A :
A,B,C,D
Because if the spinner was spinning on time it would have either landed on any of the given parts a,b,c,d once
PART B:
A and B
They are equally likely to occur because both of them have a portion of 90 degrees.
Hopefully my answer helped :)
P = 2m + 2w
Add -2w on both sides of the equations
2m = p - 2w
Divide both sides by 2
2w = p = 2m
/ 2 /2
m = 1 / 2 p - w
The key is to find the first term a(1) and the difference d.
in an arithmetic sequence, the nth term is the first term +(n-1)d
the firs three terms: a(1), a(1)+d, a(1)+2d
the next three terms: a(1)+3d, a(1)+4d, a(1)+5d,
a(1) + a(1)+d +a(1)+2d=108
a(1)+3d + a(1)+4d + a(1)+5d=183
subtract the first equation from the second equation: 9d=75, d=75/9=25/3
Plug d=25/3 in the first equation to find a(1): a(1)=83/3
the 11th term is: a(1)+(25/3)(11-1)=83/3 +250/3=111
Please double check my calculation. <span />
