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vazorg [7]
3 years ago
15

Carla has 4 packages of socks, and Jenna has 1 package of socks. Each package has 6 pairs of socks. Carla found the total number

of pairs of socks by adding (6 times 4) + (6 times 1). Jenna used a different method but got the same answer. Which strategy did Jenna use?
A. 6 + 4 + 1
B. 6 times 4 + 1
C. (6 times 1) + 4
D. 6 times (4 + 1)
Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0
The correct answer is D because you would multiply the numbers in the bracket by 6 which would equal to 30
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I think the answer is A.

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A man bought 550 oranges at 60 paisa each and 240 oranges at 50 paisa each. If he sold them at the rate of 10 for Rs 9. what was
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Answer:

hence the profit percent is 58%.

6 0
3 years ago
Ingrid makes quilts in designs that follow a specific pattern. The first three designs are shown. In designs, the white blocks r
Gekata [30.6K]

The number of white and grey blocks in the quilts follows a sequence given by the Design number of the quilt

The numbers and patterns of the blocks are;

a. Patterns;

  • The height of the white blocks is the Design number, while the rows are one more than the design number
  • The height of the outer grey blocks is 2 blocks more than the Design number, while their rows are 3 blocks more than the Design number

b. The function is \underline{p(n) = n \cdot (n + 1)}

c. The function is \underline{b(n) = (n + 2) \cdot (n + 3) -  n \cdot (n + 1)}}

d.  \underline{t(n) = (n + 2) \cdot (n + 3)  = b(n) - p(n) }

e. The design chosen is <u>Design 9</u>

The number of blocks is <u>132 blocks</u>

Reasons:

The pattern of the design are;

a. The column height of the grey blocks = 2 blocks more than the column height of the white blocks

Width of the outer grey blocks = 2 blocks more than the width of the inner white blocks

The number of white blocks in a design, <em>n</em> is the product of <em>n</em> and (n + 1)

The number of grey blocks in a design <em>n</em>, is the product of (n + 2) and (n + 3) less the number of white blocks in the design

b. Based on the above, the function that represent the number of picture blocks in Design <em>n</em>, is therefore;

  • p(n) = n·(n + 1)

c. Based on the above, the function that represent the number of border blocks in Design <em>n</em>, is therefore;

  • b(n) = (n + 2)·(n + 3) - n·(n + 1)

d. The total number of blocks, t(n) = (n + 2)·(n + 3)

t(n) = (n + 2)·(n + 3) - n·(n + 1) + n·(n + 1)

  • t(n) = p(n) + b(n)

e. The given number of picture blocks = 90

The number of picture blocks in a design, n = n × (n + 1)

Therefore, given that the number of picture blocks is 90, we have;

90 = n × (n + 1)

n² + n - 90 = 0

(n + 10)·(n - 9) = 0

n = 9, or n = -10

Therefore, the design museum chooses is <u>Design 9</u>

The total number of blocks in a quilt design, t(n) = (n + 2)·(n + 3)

Total blocks in the design the art museum choses, t(9), is given as follows;

t(9) = (9 + 2)·(9 + 3) = <u>132 blocks</u>

<u />

Learn more about series here;

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4 0
2 years ago
Reynaldo drew square EFGH. Then, he drew the image of it, square E'F'G'H', 4 centimeters to the left of the original figure. Lin
OLEGan [10]

Answer:

6 centimeters

Step-by-step explanation:

Square E'F'G'H' is just square EFGH translated to the left.

It is still the same size, just in a different location.

Line segment EF is the same length as segment E'F'.

6 centimeters

3 0
3 years ago
A rectangle is removed from the middle of a larger rectangular shaped board. What is the area of the remaining board?
jeyben [28]

Answer:

The area of the remaining board is [(L × B) - (l × b)].

Step-by-step explanation:

Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.

Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.

The area of any rectangle is:

Area = Length × Breadth

The area of the bigger rectangle is:

Area of ABCD = L × B

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Area of PQRS = l × b

Then the area of the remaining board will be:

Area of remaining board = Area of ABCD - Area of PQRS

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Thus, the area of the remaining board is [(L × B) - (l × b)].

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