Answer:
5.6 days
Step-by-step explanation:
We are given;
Initial Mass; N_o = 25 g
Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)
k = 0.1229
Formula is given as;
N_t = N_o•e^(-kt)
Plugging in the relevant values;
12.5 = 25 × e^(-0.1229t)
e^(-0.1229t) = 12.5/25
e^(-0.1229t) = 0.5
(-0.1229t) = In 0.5
-0.1229t = -0.6931
t = -0.6931/-0.1229
t = 5.6 days
Let's solve your equation step-by-step.
2(3x−1)=−6x−2
Step 1: Simplify both sides of the equation.
2(3x−1)=−6x−2
(2)(3x)+(2)(−1)=−6x+−2(Distribute)
6x+−2=−6x+−2
6x−2=−6x−2
Step 2: Add 6x to both sides.
6x−2+6x=−6x−2+6x
12x−2=−2
Step 3: Add 2 to both sides.
12x−2+2=−2+2
12x=0
Step 4: Divide both sides by 12.
12x/12= 0/12
x=0
Answer:
x=0
HOPE THIS HELPS!!! :)
Answer:
- 8° per hour
Step-by-step explanation:
Given that:
Station A = - 6°
Station B = 2°
Rate of temperature change = x° / hour ; which is the same at both stations
Temperature at station A 3 hours after the recording is the same as the temperature in station B 4 hours after the recording ;
Temperature change in Station A:
-6 + 3x
Temperature change in station B:
2 + 4x
Temperature change in A = temperature change in B
-6 + 3x = 2 + 4x
Collect like terms
3x - 4x = 2 + 6
- x = 8
x = - 8
Hence, the rate of temperature change x in both stations is - 8° per hour
Answer:
10z+34
Step-by-step explanation:
