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2 years ago

Find the measurement of angle ABC

Mathematics

1 answer:

liq [111]2 years ago

4 0

First you have to solve for the other angle (3x-70) so, 3x=70 and x=70/3

now that you have the complementary angle of 70/3 degrees, subtract 180-70/3 to get 156 2/3 degrees as your final answer

You might be interested in

Una empresa comercial vende automóviles cuyo precio es de S/. 60 000, con una cuota inicial del 20%, para cancelar el saldo en 3

Inessa05 [86]

Responder:

2560

Explicación paso a paso:

Dado lo siguiente:

Precio del automóvil = 60000

Cuota inicial = 20% del precio = (0.2 * 60000 = 12,000

Saldo = (60000 - 12000) = 48000

La empresa cobra un interés simple del 12% cada 6 meses

Periodo de pago = 30 meses / 6 = 5 periodos

Interés simple: p * r * t

= 48000 * 0,12 * 5 = 28800

Por lo tanto, monto total a reembolsar, incluidos los intereses:

Balance + 28800; 48000 + 28800 = 76800

El reembolso mensual es fijo;

Por lo tanto,

76800/30 = 2560

4 0

2 years ago

Set up a proportion and solve each problem. Round each answer to the nearest tenths. 5) What is 35% of 74? 6) 78 is what percent

prisoha [69]

Answer:

5) 35 / 100 = X / 74 X = 2590 / 100 = 25.9

or .35 * 74 = 25.9

6) 78 / 95 = X * 100

X = 7800 / 95 = 82.1 %

or X = 78/95 * 100 = 82.1 %

7) 60/100 * X = 28

X = 2800 / 60 = 46.7

Or .6 * X = 28

X = .28 / .6 = 46.7

8 0

2 years ago

In a certain chemical, the ratio of zinc to copper is 4 to 15. A jar of the chemical contains 750 of copper. How many grams of

nataly862011 [7]

Answer: it contains 200 grams of zinc.

Step-by-step explanation:

Ratio of zinc to copper is 4 to 15 = 4;15

Total ratio = 4+15= 19

We first find amount of both zinc and copper( the whole chemical) which is equal to

ratio of copper / total ratio x (the entire chemical--total grams of zinc and copper) =amount of copper

15/19 x X = 750

X= 750 X 19 / 15= 950 grams

To find amount of zinc in the chemical = ratio of zinc / total ratio x total amount of chemical

=4/19 x 950

=200 grams

3 0

2 years ago

Which is the graph of FX=

jekas [21]

Answer:

F(x) is simply another name for y. therefore they all are graphs for F(x) just different equations.

Step-by-step explanation:

4 0

2 years ago

For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;

Dmitrij [34]

Answer:

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

$ax+by=c$

Suppose integers x0 and yo satisfy the equation; that is,

$ax_0+by_0 = c$

what other values

$x = x_0+h$ and $y=y_0+k$

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

$as+bt=gcd(a,b)$

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

$a(sk) + b(tk) = gcd(a,b)k = c$

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

$a(x_1-x) + b(y_1-y)=0$

Therefore,

$a(x_1-x) = b(y-y_1)$

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

$y = y_1+r(\frac{a}{gcd(a, b)})$ for some integer r. Substituting into the equation

$a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba$

$x = x_1-r(\frac{b}{gcd(a, b)} )$

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

$15 = 6*2+3\\6=3*2+0$