Using the speed - distance relationship, the number of minutes it will take Josiah to cover a distance of 2.5 miles is 30 minutes.
<u>Calculating Josiah's speed</u> :
- <em>Speed = (distance ÷ time) </em>
Speed = (3 ÷ 36) = 0.08333 miles per minute.
<u>Time taken to cover a distance of 2.5 miles</u> :
- <em>Time taken = (Distance ÷ Speed) </em>
Time taken = (2.5 ÷ 0.08333) = 30 minutes
Therefore, it will take 30 minutes for Josiah to cover a distance of 2.5 Miles
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Answer:
We conclude that it is possible for an object to have more than one input value, but only one output value.
Step-by-step explanation:
Yes, it is possible for an object to have more than one input value, but only one output value.
For example, considering the table having 'name' as the 'input' and the output as 'age'.
Name of Relatives Age (years)
Mr A 13
Mr B 14
Mr C 13
Mr D 15
Here, Each input has only input. But, multiple relatives can have the same age.
Here, Mr A and Mr C have the same 13 years age. This table represents a function.
Therefore, we conclude that it is possible for an object to have more than one input value, but only one output value.
Answer:
-22/3
Step-by-step explanation:
I'm assuming you want the improper fraction of -7 1/3.
Multiply the denominator of 1/3 (which is 3) by -7, which should give you -21. Add the remaining of the numerator of the fraction, (which is 1) to get -22. Put that over 3, and you get -22/3.
here's the work:
-7 1/3
= -(21+(-1))/3
=-22/3
Answer:
9.43 cm³
Step-by-step explanation:
Given that the surface area of the spherical scoop is 36π cm², we find its radius. The surface area of a sphere, A = 4πr² where r = radius
36π cm² = 4πr²
r² = 36π cm²/4π
r² = 9 cm²
r = √(9 cm²)
r = 3 cm
So, the volume of the spherical scoop of ice cream is thus V = 4πr³/3
= 4π(3 cm)³/3
= 4π(9 cm³)
= 36π cm³
The volume of the ice cream cone is V' = πr²h/3 where r = radius of cone = radius of spherical scoop = 3cm and h = height of cone = 11 cm
V' = π(3 cm)² × 11 cm/3
= 9π cm² × 11 cm/3
= 33π cm³
So, the volume of ice cream that will overflow is thus V - V' = 36π cm³ - 33π cm³
= 3π cm³
= 9.43 cm³