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2 years ago

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The cost price of a box and a pen is Rs 80 The box is sold at 10% profit and the pen is sold at 20% loss. If the selling price o

f the box is Rs 28 more than that of the pen, calculate the profit or loss percent in a whole.

1 answer:

uysha [10]2 years ago

4 0

Answer:

61.84%

Step-by-step explanation:

Let the cost of the box be x. Since the price of the box and the pen is Rs 80, the pen's price can be represented as 80 - x. The box is sold at a ten percent profit, and an added ten percent is equal to 1.1. Therefore, the price the box sells at is 1.1(x). A 20% loss is the same a keeping 80% or multiplying by 0.8. This means the pen sold at 0.8(80 - x). Now, we are given the box went for Rs 28 more than the pen, so we can create an equation:

1.1x = 0.8(80 - x) + 28

We can simplify and solve:

1.1x = 64 - 0.8x + 28

1.9x = 92

x = 92/1.9

x = 920/19

The cost of the box after the increase would be 1.1(920/19) and the pen would be 0.8(80 - 920/19).

The sum of these two can be written as a percent x of 80.

80x = 0.8(80 - 920/19) + 1.1(920/19)

80x = 64 - 0.8(920/19) + 1.1(920/9)

80x = 64 - 0.3(920/19)

80x = 64 - 276/19

80x = 940/19

x = 940/1520

x = 0.6184

This is 61.84%

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Answer:

a. Not Divisible

b. Divisible

c. Divisible

d. Divisible

e. Divisible

Step-by-step explanation:

To find the divisibility we need to follow the PEMDAS rule and check if the total value can be divided by the selected numbers without returning a remainder.

Let's begin with a:

$16^{5}+215$ by 33

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$1,048,791$

We now then divide the total amount with 33.

$\dfrac{1,048,576}{33}$

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Now let's continue on with the others.

$51^{7}-51^{6}$ by 25

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$879,814,390,050$

We now then divide the total amount with 25.

$\dfrac{879,814,390,050}{25}$

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The total value did NOT return a decimal point, therefore making the equation true. $51^{7}-51^{6}$ IS divisible by 25.

Next on we have:

$5^{5}-5^{4} +5^{3}$ by 7

$3,125 - 625 + 125$

As we know in the PEMDAS rule, that addition comes first. In this situation we have to read the equation from left to right and solve which ever comes first.

$2,500 + 125$

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We now then divide the total amount with 7.

$\dfrac{2,625}{7}$

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The total value did NOT return a decimal point, therefore making the equation true. $5^{5}-5^{4} +5^{3}$ IS divisible by 7.

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$117,649+16,807-2,401$

$134,456-2,401$

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We now then divide the total amount with 11.

$\dfrac{132,055}{11}$

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The total value did NOT return a decimal point, therefore making the equation true. $7^6+7^5-7^4$ IS divisible by 11.

Last but not the least:

$5^{23}-5^{21}$ by 24

$11,920,928,955,078,125-476,837,158,203,125$

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We now then divide the total amount with 24.

$\dfrac{11,444,091,796,875,000}{24}$

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The total value did NOT return a decimal point, therefore making the equation true. $5^{23}-5^{21}$ IS divisible by 24.

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3 years ago

What is the answer for -7 +4

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Step-by-step explanation:

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2 years ago

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weqwewe [10]

Answer:

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Step-by-step explanation:

Given:

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Find:

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Computation:

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2 years ago

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Answer:

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Step-by-step explanation:

Given the data in the question;

Binomial distribution

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⇒ πR₁² / πR₂²

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so we substitute

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so

X ~ Bin( 2000, 0.04 )

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np = 2000 × 0.04 = 80

Using central limit theorem;

X ~ N( np, np( 1 - p ) )

we substitute

X ~ N( 80, 80( 1 - 0.04 ) )

X ~ N( 80, 80( 0.96 ) )

X ~ N( 80, 76.8 )

So, the probability that we hit the bullseye at least 100 times, P( X ≥ 100 ) will be;

we covert to standard normal variable

⇒ P( X ≥ $\frac{100-80}{\sqrt{76.8} }$ )

⇒ P( X ≥ 2.28217 )

From standard normal distribution table

P( X ≥ 2.28217 ) = 0.0113

Therefore, the probability that we hit the bullseye at least 100 times is 0.0113

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