All categories

3 years ago

Point C is in the interior of

Mathematics

1 answer:

PolarNik [594]3 years ago

8 0

Answer:

Point C is in the interior of angle ABD.

You might be interested in

Fabio and Carlos play on a basketball team together. In the last game, Fabio had

Andreas93 [3]

Answer:

19 points

Step-by-step explanation:

Given that :

Fabio had 7 points less than 2 times as many points as Carlos

Let Fabio's point = f

Carlos point = c

Equation relating the number of points scored by both players.

Points scored by Fabio = 31

f = 2c - 7

Carlos point = c

31 = 2c - 7

31 + 7 = 2c

38 = 2c

c = 38/2

c = 19

Hence, Carlos's points is 19

8 0

3 years ago

What is the value of the product (3 - 2i(3 + 2i?

ZanzabumX [31]

Answer:

i is always positive

Step-by-step explanation:

if be multiply 3 by 3 and get 9, then you multiply -2i by 2i and get -4i squared

9-4i^2 is now easy to solve unless we do now know the value of i, but since i is squared, i is always positive

7 0

3 years ago

Read 2 more answers

An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f

Sphinxa [80]

Answer:

Distance between plane and airport is 134.4 miles.

Step-by-step explanation:

Given : An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W.

To find : How far is the plane from the airport.

Solution : Distance from airport to west is 150 miles and then 170 miles in the direction south and angle form is S 49.17° W

Refer the attached picture for clearance.

Applying law of cosines

$c^2=a^2+b^2-2ab Cos(C)$

$c=\sqrt{a^2+b^2-2ab Cos(C)}$

where a= 150 miles

b=170 miles

C= 49.17° angle in degree

c = distance between plane from the airport

Put values in the formula,

$c=\sqrt{a^2+b^2-2ab Cos(C)}$

$c=\sqrt{150^2+170^2-2(150)(170) Cos(49.17^{\circ})}$

$c=\sqrt{22500+28900-51000(0.653)}$

$c=\sqrt{51400-33303}$

$c=\sqrt{18057}$

$c=134.37$

Therefore, Distance between plane and airport is 134.4 miles.

5 0

3 years ago

Read 2 more answers

There are 250 bricks used to build a wall that is 20 feet high. How many bricks will be used to build a wall that is 30 feet hig

Harrizon [31]

If there are 250 bricks in a 20 feet high wall, there should be 125 bricks in a 10 feet high wall.

So to get a 30 feet high wall, you need to multiple 125 bricks by 3.

6 0

3 years ago

Read 2 more answers

Can 2x1/10 be 2.0 because that is the only answer I get

nika2105 [10]

Im pretty sure it would be 0.2

6 0

4 years ago

Read 2 more answers