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2 years ago

PLEASE HELP!!!

Mathematics

2 answers:

AfilCa [17]2 years ago

7 0

The answers must be B

Ivenika [448]2 years ago

5 0

Answer:

Step-by-step explanation:

(Standard form is automatically in integers)

Multiply by 3 to take out the fraction

3y=2x+21

-2x -2x

-2x+3y=21

Standard form means Ax+By=C with positive A (usually--some people allow A to be negative).

Multiply by (-1)

2x-3y=-21

(Technically, that's the more correct answer, but since you don't have that choices, it's just the previous one.)

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Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

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3 years ago

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pochemuha

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2 years ago

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Hello there!

How do you find the y-intercept?

Answer: To find the y-intercept, substitute in 0 for x and solve for y

y = x² + 3x + 5

y = (0)² + 3(0) + 5

y = 0 + 0 + 5

y = 5

Thus, the correct answer is option D (0,5)

I really hope this answer is clear enough for you to understand. If you have questions about the answer, please let me know.

As always, I'm glad to be your helper this evening~!

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Step-by-step explanation:

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