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kaheart [24]
3 years ago
9

PLEASE HELP!!!

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0
The answers must be B
Ivenika [448]3 years ago
5 0

Answer:

B

Step-by-step explanation:

(Standard form is automatically in integers)

Multiply by 3 to take out the fraction

3y=2x+21

-2x -2x

-2x+3y=21

Standard form means Ax+By=C with positive A (usually--some people allow A to be negative).

Multiply by (-1)

2x-3y=-21

(Technically, that's the more correct answer, but since you don't have that choices, it's just the previous one.)

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dimaraw [331]

Answer:

Step-by-step explanation:

-35/2 x (-21/5)

-7/2 x (-21/1)

-7/2 x (-21) = 147/2= 78 1/2

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3 years ago
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WILL GIVE BRAINIEST 100 PIONTS
antiseptic1488 [7]
Liar. This is only worth 5 points!!!!!!!!!!!!!!!!!!!!
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Paisley's car used 11 gallons to travel 374 miles. How many gallons of gas would she need to travel 442 miles?
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Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The goal is to sh
natulia [17]

Complete Question

Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.

Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.

Answer:

P(18) is true

P(19) is true

P(20) is true

P(21) is true

Step-by-step explanation:

a. When n = 18

18 cents can be formed using two 7cents and one 4cents

i.e. 2 * 7 + 4 = 18

So, P(18) is true

b. When n = 19

19 cents can be formed using one 7cents and three 4cents

i.e. 1 * 7 + 3 * 4 = 19

So, P(19) is true

c. When n = 20

18 cents can be formed using five 4cents

i.e. 5 * 4 = 20

So, P(20) is true

d. When n = 21

18 cents can be formed using three 7cents

i.e. 3 * 7 = 21

So, P(21) is true

7 0
3 years ago
Part A<br> Rewrite 0.5 as an exponential expression with a base of 2.
koban [17]

Answer:

2^{-1}

Explanation:

05/10

Simplifying

1/2

or 2^-1

Hope this helps you. Do mark me as brainlist

4 0
2 years ago
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