Answer:
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Answer:
yes the Bohr model predicts their spectra accurately
Explanation:
The Bohr model based on one electron system
The atom H has a single atom and the ion Be+3 has a single atom as well and this proves that the Bohr model predicts their spectra accurately .
also apply the equation model to further explain
E = 
z = atomic number
for H the value of z = 1
for Be+3 the value of z = 4
when this values are substituted into the equation above
E = 
, E = 
this results show that the energy level of Be+3 is higher than the energy level of H by a factor of 16 , and this shows that their line patterns are similar
Regretfully, I do not know what is asked of the problem because it is not stated above. However, it is easier to answer any question pertaining to the temperature, volume, and pressure of gases by assuming that they behave ideally. With this, we'll be able to use the ideal gas law which is mathematically expressed as,
PV = nRT
where P and V are pressure and volume, respectively. n is the amount of material in mol, R is gas constant, and T is temperature.
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:
C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
Answer: Option (A) is the correct answer.
Explanation:
According to the Gibb's free energy conditions:
If 
< 0, then reaction is spontaneous.
If > 0, then reaction is non-spontaneous.
If = 0, then reaction is equilibrium.
Since, the given reaction is 
. It denotes that liquid state of fluorine is changing into gaseous state. And, the boiling point of fluorine is very low.
Therefore, at low and high temperature fluorine is a gas. Hence, the reaction is spontaneous in nature.
Thus, we can conclude that the statement at low temperature, the reaction is spontaneous and < 0 and at high temperature, the reaction is spontaneous and < 0, is correct.
