Dipole-Induced-Dipole is the strongest type of intermolecular force between solute and solvent.
<h3>What is Intermolecular Force ?</h3>
Intermolecular force is also called secondary force is the force of attraction between molecules. It acts between ions and atoms.
<h3>What is Dipole-Induced-Dipole attraction ?</h3>
A dipole-induced-dipole attraction is a weak attraction it occurs when the partial charge form with in the molecule due to uneven distribution of charge in a molecule.
CCl₄ is non polar in nature and CH₃OH is polar in nature so dipole-induced-dipole attraction is present.
Thus from the above conclusion we can say that Dipole-Induced-Dipole is the strongest type of intermolecular force between solute and solvent.
Learn more about the Dipole-Induced-Dipole here: brainly.com/question/22973877
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Answer:
It is an example of chemical reaction because carbon dioxide and water are converted into glucose and oxygen. If that makes any sense. and it is classified as endothermic because it requires the input of energy in the form of solar energy.
Explanation:
<u>Answer:</u> In a chemical reaction, the total mass of the particles in the system stays the same
<u>Explanation:</u>
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side in a chemical reaction.
Every balanced chemical reaction follows law of conservation of mass.
<u>For Example:</u> Formation of water molecule

Total mass on reactant side = ![[2(2\times 1)+(2\times 16)]=36g/mol](https://tex.z-dn.net/?f=%5B2%282%5Ctimes%201%29%2B%282%5Ctimes%2016%29%5D%3D36g%2Fmol)
Total mass on product side = ![[2((2\times 1)+16)]=36g/mol](https://tex.z-dn.net/?f=%5B2%28%282%5Ctimes%201%29%2B16%29%5D%3D36g%2Fmol)
Hence, in a chemical reaction, the total mass of the particles in the system stays the same
Answer:
The molar solubility of lead bromide at 298K is 0.010 mol/L.
Explanation:
In order to solve this problem, we need to use the Nernst Equaiton:
![E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}](https://tex.z-dn.net/?f=E%20%3D%20E%5E%7Bo%7D%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%5Cfrac%7B%5Box%5D%7D%7B%5Bred%5D%7D)
E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.
At equilibrium, E = 0, therefore:
![E^{o} = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] = log[ox] - \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] - \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 - \frac{2x5.45x10^{-2} }{0.0591}}\\\\](https://tex.z-dn.net/?f=E%5E%7Bo%7D%20%20%3D%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5Box%5D%7D%7B%5Bred%5D%7D%20%5C%5C%5C%5Clog%20%5Cfrac%7B%5Box%5D%7D%7B%5Bred%5D%7D%20%3D%20%5Cfrac%7BnE%5E%7Bo%7D%20%7D%7B0.0591%7D%20%5C%5C%5C%5Clog%5Bred%5D%20%3D%20%20log%5Box%5D%20-%20%20%5Cfrac%7BnE%5E%7Bo%7D%20%7D%7B0.0591%7D%5C%5C%5C%5C%5Bred%5D%20%3D%2010%5E%7B%20log%5Box%5D%20-%20%20%5Cfrac%7BnE%5E%7Bo%7D%20%7D%7B0.0591%7D%7D%20%5C%5C%5C%5C%5Bred%5D%20%3D%2010%5E%7B%20log0.733%20-%20%20%5Cfrac%7B2x5.45x10%5E%7B-2%7D%20%20%7D%7B0.0591%7D%7D%5C%5C%5C%5C)
[red] = 0.010 M
The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.