Which sample contains the most concentrated solution of hydrochloric acid (HCl)?

What is the pH of an acetic acid solution where the concentration of acetic acid is 2 mM and the concentration of sodium acetate

schepotkina [342]

Answer:

pH = 5.76

Explanation:

We can solve this problem by using Henderson-Hasselbach's equation:

pH = pKa + log $\frac{[SodiumAcetate]}{[AceticAcid]}$

We are already know all the required information, thus we input the data given by the problem:

pH = 4.76 + log(20/2)

And finally calculate the pH:

pH = 5.76

The pH of that acetic acid solution is 5.76.

6 0

3 years ago

What is an Alkanoate?

Vlad1618 [11]

Answer: Alkanoate (plural alkanoates) (organic chemistry) Any salt or ester formed from the reaction of an alkaloic acid and alkaloids

Explanation: I looked in my dictionary and found this. I hope this helped

6 0

3 years ago

What happened when we made the predator(snake) population larger?

jeka57 [31]

Answer:

The rabbit prey population will decrease.

Explanation:

More predators are there to eat the prey

3 0

3 years ago

A balloon filled with helium gas has a volume of 500 mL at a pressure of 1 atm. The balloon is released and reaches an altitude

Rasek [7]

We are using the General gas equation P x V/K = P x V/K
1. P = 1atm V=500ml so PxV= 500 at 6.5km P = 0.5atm V = ? so P xV = 0.5 x V
(We don't have to worry about temperature!) 500 = 0.5 x V so V = 1000ml

2. NO CHANGE in pressure here so we have V/K V=2.75 K = 20 + 273=293 so V/K= 2.75/293
Next set V = 2.46 K = ? so V/K = 2.46/K then 2.75/293= 2.46/K so K=(293/2.75)x2.46
=262 K
Convert back to Celsius 262 - 273 = -11 C
It's raining so I have to rescue the laundry!
Laundry rescued!

3.Now we have to use all three variables. I am using 273K and 100kPa for STP.
P = 100 V = 700 K = 273 These are altered P - unknown, V = 200 K = 273+30=303
!00 x 700/273 = 256.4 this is equal to P x 200/303 = P x 0.66
so P = 256.4/0.66 = 388.48kPa

7 0

4 years ago

Read 2 more answers

A student obtains a mixture of the chlorides of two unknown metals, X and Z. The percent by mass of X and the percent by mass of

Aleksandr-060686 [28]

Answer: The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

Explanation:

To calculate the mole percent of a substance, we use the equation:

$\text{Mole percent of a substance}=\frac{\text{Moles of a substance}}{\text{Total moles}}\times 100$

Mass percent means that the mass of a substance is present in 100 grams of mixture

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We require the molar masses of Z and X to calculate the mole percent of Z and X respectively

Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

8 0

3 years ago