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cricket20 [7]
3 years ago
8

Audrey went shopping at a kids' clothing store where the shirts and

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0
100-2=98

6clothes+8clothes=14clothes.

98/14=7.

$7.
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Today is Leilas birthday. She is 5 years old. How old is leila in months
olga_2 [115]

Answer:

60

Step-by-step explanation:

There are 12 months in a year, so 5 years×12 months=60 months.

**You may wish to revise multiplication or the calendar year. I'm always happy to help

8 0
2 years ago
Read 2 more answers
You and a friend went to the movies.You spent half your money on tickets. Then you spent 1/4 of the money on popcorn, $2 on cand
bagirrra123 [75]

Answer:

We took $ 24 to the movies.

Step-by-step explanation:

Let total money be

On movies = Half of the money =\frac{x}{2}

On popcorn =  \frac{x}{4}

on candy = $2

On soda = $3

total money spent =  \frac{x}{2} +\frac{x}{4}+ 2+3+1

         x   =  \frac{x}{2} +\frac{x}{4}+ 2+3+1

x- \frac{x}{2} -\frac{x}{4} = 6

\frac{x}{1} -\frac{x}{2} - \frac{x}{4}  =6

    \frac{4x-2x-x}{4}  = 6\\          \frac{x}{4} =6\\x =24

3 0
3 years ago
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
Find the y intercept of the line on the graph
saul85 [17]
It’s the vertical line on the graph
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2 years ago
Someone please help me will give BRAILIEST!!!!!!
Kipish [7]
The answer would be 15
6 0
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