Answer:
I believe the answer is (-7.4) Not really great at math either
Step-by-step explanation:
The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
Answer:
9=0.6q where q is the number of questions on the exam.
Step-by-step explanation:
Step-by-step explanation:
the volume of a cylinder is as for any other regular 3D object :
ground area ×height
the ground area of a cylinder is a circle, so it is
pi×radius² × height
the radius is always half of the diameter (of the diameter is airways twice the radius).
radius = 6/2 = 3 ft.
the volume is then
pi × 3² × 9 = pi × 9 × 9 = pi × 81 ft³
so, the answer is 81pi ft³.
Answer:
Step-by-step explanation:
The input-output table can be made by putting value of x and finding the value of f(x)
f(x) = 3x^2-x+4
f(0) = 3(0)^2-0+4 = 0-0+4 = 4
f(1) = 3(1)^2-1+4 = 3-1+4 = 2+4 =6
f(2) = 3(2)^2-2+4 = 3(4)-2+4 = 12-2+4 = 10+4 = 14
f(3) = 3(3)^2-3+4 = 3(9)-3+4 = 27-3+4 = 24+4 = 28
So put value of x and find f(x) and fill the input-output table.
x f(x)
0 4
1 6
2 14
3 28
